Chemistry unit 6

A reversible isomerisation U to V has ΔH = +12 kJ mol-1 and ΔS = +40 J mol-1 K-1, treated as constant between 250 and 400 K. Standard free energy is ΔG° = ΔH-TΔS. Equilibrium obeys ΔG° = -RT ln K, with K=[V]/[U] and R positive. A catalyst changes activation barriers but not the energies of U and V. The closed system contains only these two isomers.

  1. Question 1
  2. Question 2
  3. Question 3
  4. Question 4
  5. Question 5
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At what temperature is K=1?

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